The message
from The Natural Philosopher contains these words:

You do know that incomplete burning of propane to produce CO also
produces
the same amount of hydrogen which could blow your place to bits.

Does the fire authority know you carry out such a potentially dangerous
operation?

Very unlikely. The hydrogen has a far greater affinity for the oxygen than
the carbon.

So how accurate is the formula dennis@home previously stated?

"C3H8 + 4(O2+4N2) === CO + 2CO2 + 3H2O + H2 + 16 N2"

I am no chemist but ISTM that that could equally well be written as:

C3H8 + 4(O2+4N2) === 2CO + CO2 + 4H2O + 16 N2

--
Roger Chapman