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Gunner
 
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Default Tungsten electrodes for armor piercing bullets

On Thu, 3 Nov 2005 22:22:15 -0800, "Harold and Susan Vordos"
wrote:


"Ignoramus12686" wrote in message
...
On Thu, 03 Nov 2005 14:24:15 GMT, Dave Lyon

wrote:

"Ignoramus26745" wrote in message
...
On 2 Nov 2005 21:35:18 GMT, Dave Hinz wrote:
On Wed, 02 Nov 2005 21:27:03 GMT, Dave Lyon
wrote:

My understanding is that every action has an equal and opposite
reaction.
Therefore, the energy that is applied to the bullet must be absorbed

by
the
gun and the shooter in the opposite direction.


Snipped the other Dave's comments


OK, today I am actually sober.

Let's not confuse energy with momentum.

Apparently I am (still).


Momentum is mass multiplied by speed. Energy is mass multiplied by
speed squared, divided by 2. Momentum is a vector and has direction
(the direction of movement), and energy is scalar, it is a single
value.

So, momentum is the same thing as acceleration?


No, it is not the same thing. Acceleration is tha rate of change of
speed of movement. Momentum is mas multiplied by speed of movement.

Unless the bullet weighs exacty as much as the gun,
there is no reason to expect energies of the gun and the bullet to be
the same.


This is where I get lost. If the acceleration of both items is

proportional
to their weight, why wouldn't their energy be the same?


Acceleration (speed increase) is inversely proportional to the weight.

Energy is mass by speed squared. If one object's mass is 10 times the
mass of another object, that another (lighter) object would fly 10 times
faster than the heavy object. The energy of the lighter object would
be a result of 10 times greater speed, squared (100 times), divided by
the difference of mass, 10, so it would be 100/10 = 10 times greater
than the energy of heavy object.

I understand that
the larger item is moving slower, and the smaller one is faster. I don't
understand why their ability to do a given amount of work would be
different.

If I apply 1000 newtons of force to any size object to get it
moving, assuming we didn't loose anything to friction, won't we need
1000 newtons to make it stop? Doesn't that mean they have the same
energy?


No.

For example, you can accelerate a sledgehammer using, say, 100 newtons
of force. That would accelerate it relatively slowly.

Then the sledgehammer would hit concrete, stopping very quickly. That
could easily produce, say, 10,000 newtons of force, although acting
for much shorter time than it took you to accelerate the sledgehammer.

The time multiplied by force value, though, would be identical for you
accelerating the sledgehammer as well as for concrete stopping it. In
the above example, it would take concrete 100x less time to stop the
sledgehammer compared to the time it took you to accelerate it.

i


I'm no mathematician, and have a hard time understanding almost all of this
conversation, but to illustrate a point (if only I knew which
one!)-------the .458 Magnum I own develops 2-1/2 tons of energy at the
muzzle, assuming a maximum load with a 500 grain bullet. It stands to
reason that there's hardly a man alive that could withstand that force on
his shoulder and survive, let alone still be standing. My rifle does NOT
have a muzzle break, and develops 80 foot pounds of recoil (about triple
that of a 12 gauge shotgun) , at least according to the things I read years
ago. It doesn't knock you down. Not unless you're an idiot. :-(
Please, don't ask.

Harold

Try shooting one,while prone. One owned by a fellow with a very short
neck.

My 375 H&H Magnum is a bit rough when prone...the 458 Ackley is a
stone bitch.

Gunner, Member of the Order of the Scarlet Crescent. (2 chevrons)


"Pax Americana is a philosophy. Hardly an empire.
Making sure other people play nice and dont kill each other (and us)
off in job lots is hardly empire building, particularly when you give
them self determination under "play nice" rules.

Think of it as having your older brother knock the **** out of you
for torturing the cat." Gunner