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Metalworking (rec.crafts.metalworking) Discuss various aspects of working with metal, such as machining, welding, metal joining, screwing, casting, hardening/tempering, blacksmithing/forging, spinning and hammer work, sheet metal work. |
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Kinda OT - a simple "mechanics" question
Let's say there's a lever with 3 forces acting on it:
1 2 3 V_________________________V____________V /\ let F1, F2, & F3 be the forces and L1, L2, & L3 be the distances of those forces from the fulcrum. Then F1*L1 = F2*L2 + F3*L3 Simple enough. Now, let's say that F1 is a fixed force (e.g., a weight sitting on the lever). Then F2 & F3 could be any combination of forces, as long as it balances. Now say that points 2 & 3 are fixed. I.e., the lever is "tied down" at those points. What are the forces acting on those tie downs? Is the torque (moment of inertia, if you will) attributable to each equal, so that the forces are inversely proportional to the distances? I.e.: F2*L2 = F3*L3 (= 1/2 F1*L1) It seems intuitively so, but if it is, how do you show that it is? This has been bugging me for days, so any resolution that you can offer will be greatly appreciated. Bob |
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