Simple way of making Golf Ball with Solidworks!
 

On Sat, 4 Mar 2006 10:57:52 +0200, "Heikki Leivo"
wrote:

"TOP" wrote in message
oups.com...
If you look at the link it seems to be what they did on some golf
balls. You cannot project a sketch, but you can get points from a
sketch to project onto a surface. Very tedious, but doable.

The easiest way to do the dimples is to use the hole wizard. Hole wizard is
basically a revolve, and you can edit the hole profile to represent a
dimple. You can model a 1/6 piece of one icosahedron triangle, cut it to
sphere shape, use hole wizard to create four dimples and finally use body
mirrors and patterns to create the ball shape.

While a regular (platonic) icosahedron has 20 faces it has only 12 vertices.

[
Most balls on sale today have about 300 to 450 dimples. There were a few balls
having over 500 dimples before. The record holder was a ball with 1,070 dimples
-- 414 larger ones (in four different sizes) and 656 pinhead-sized ones. All
brands of balls, except one, have even-numbered dimples. The only odd-numbered
ball on market is a ball with 333 dimples.
] from TOP's link : http://www.answers.com/topic/golf-ball g.

G. De Angelis chose 330.

12=2*3*2^2
20=5*2^2

330=2*3*5*11
300=(2^2)*3*(5^2)
333=3*111
414= 2*207
450= 2*(3^2)*(5^2)
656 =(2^4)*41
1,070= 2*5*107

You may be able to design a golf ball based on icosahedrons
IF it has 300 dimples.
Not in the other cases I suspect though you might try using both
faces & vertexes .... 32 = 2^5 .... Nope.

Or am I wrong G?
--
Cliff

Simple way of making Golf Ball with Solidworks!
 

"Cliff" wrote in message
...

You may be able to design a golf ball based on icosahedrons
IF it has 300 dimples.
Not in the other cases I suspect though you might try using both
faces & vertexes .... 32 = 2^5 .... Nope.

Or am I wrong G?

Yes you are, indeed. Did you try to model it? I modeled the left golf ball
depicted in
http://content.answers.com/main/cont...ll_designs.jpg

It has one dimple per each icosahedron vertex, four per edge and six dimples
per face, eg. 12*1 + 20*6 + 30*4 = 252 dimples.

I don't know how to arrange the dimples to get exactly 300 dimples.
-h-

Simple way of making Golf Ball with Solidworks!
 

On Sat, 4 Mar 2006 12:51:40 +0200, "Heikki Leivo"
wrote:

"Cliff" wrote in message
.. .

You may be able to design a golf ball based on icosahedrons
IF it has 300 dimples.
Not in the other cases I suspect though you might try using both
faces & vertexes .... 32 = 2^5 .... Nope.

Or am I wrong G?

Yes you are, indeed. Did you try to model it? I modeled the left golf ball
depicted in
http://content.answers.com/main/cont...ll_designs.jpg

It has one dimple per each icosahedron vertex, four per edge and six dimples
per face, eg. 12*1 + 20*6 + 30*4 = 252 dimples.

I don't know how to arrange the dimples to get exactly 300 dimples.
-h-

To begin with, 252 was not on the list G.

252=(2^2)*63 .....

To recap:
12=2*3*2^2
20=5*2^2

But you also used 6 per face and 4 per edge .. does that include
the vertex ones?
Probably not very uniform in spacing either ....

Someone might try lesser Platonic solids too ...
--
Cliff