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Figuring loads / block & tackle theory
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Figuring loads / block & tackle theory
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Figuring loads / block & tackle theory
In article , (Harry K) wrote:
(Doug Miller) wrote in message gy.com... In article , (Harry K) wrote: "Greg O" wrote in message ... "Michael Daly" wrote in message ... On 16-Mar-2004, (Doug Miller) wrote: You know that, I know that, Mike knows that I can't help but notice that he hasn't responded to a single one of my posts. Mike Mike, I apologize if I missed you but I don't see any in my google reader. I just reviewed the entire list of posts and still don't see any. If you have a point that hasn't been raised try again or put it to one of Greg or Doug's. The only points that have been raised by any of them all come down to -you are wrong, you are lying- and the like. None have posted any research, only one claims to have done the test and he lied about the results. No, Harry, it is _you_ who is lying about results. Or about your test setups. One or the other. The setups you purport to be measuring simply don't give the results you report. We're still waiting for the photos of your setups, Harry. And I was going to, actually was there to borrow a camera, but said why? You will only claim I am faking. ROTFLMAO! Still waiting for your photos, Harry.... See my other post to Greg for a cite. I am still looking for a better one but not holding any hopes. That cite does *not* in any fashion support your claims. As predicted you would say 'that is wrong' with nothing behind it. You haven't done any research at all. Read what I wrote, fool. I didn't say that anything on that site was wrong. I said it doesn't support your claims. And it doesn't. Yet you continue to falsely claim that it does. You're a liar, Harry. |
Figuring loads / block & tackle theory
In article , (Harry K) wrote:
(Doug Miller) wrote in message gy.com... In article , (Harry K) wrote: Douglas and Rosemarie Miller wrote in message gy.com... In article , says... [big snip] Someone way up thread posted at link to a site giving the good explanation. Once again, Harry, you're caught in a lie. The site posted does *not* support your position here, despite your false claim that it does. Here's the relevant part of the post you refer to: http://www.howstuffworks.com/pulley.htm This web page speaks to the issue of how much pull is needed on the rope to make the weight go up. But it does not adress the felt weight on the pulley hook. Note that last sentence, Harry: "does not adress [sic] the weight on the hook". And just where did I say that it did? I said that someone had posted a link, you found it. I didn't read it. You apparently haven't read very much of anything -- including what you yourself have written. You said that the link was to "a site giving the good explanation." In fact, that site doesn't explain *anything* that is relevant to this discussion. One citation, Harry, just *one*, of a published source that supports your claims. Just one. We're waiting. See below. I gave a cite and jsut as I predicted you said it was wrong. Harry, when are you going to stop lying? I did _not_ say the site was wrong. I said it does not support your claims. And it doesn't. But you continue to falsely claim that it does, even though it never mentions the one point that we're arguing about. You're a liar, Harry. |
Figuring loads / block & tackle theory
In article , (Harry K) wrote:
(John Cochran) wrote in message ... In article , Harry K wrote: (John Cochran) wrote in message ... SNIP No it isn't. If you tie the other end of the rope to the load instead of the anchor, this is what you get. | | O | | | | | | This half ----- | | --- This half of the rope has 20 lbs of tension. of the rope | | has 20lbs of | | tension | | | | +---+-+--+ | 40 lbs | +--------+ For the situition that you have | | O\ | \ | \ This half ------ | \ --- This half of the rope has 40 lbs of tension of the rope has | \ 40 lbs of | \ tension | \ | \ | . Anchor +----+---+ | 40 lbs | +--------+ No matter how you do it, in order to support the 40lb load, the sum of all ropes attached to the load has to add up to 40lbs. If you're using a simple pulley at the top and attach both ends of the rope to the load, then the rope has a tension of 20lbs and both sides add up to a total of 40 lbs. If you instead attach one end of the rope to an anchor, then the rope has an tension of 40 lbs and the hook at the top is having to support a total of 80 lbs. The weight will remain quite nicely right where it is. What is the pull on the hook?? Where did the 40 lbs go?? I hope you answer this as you do appear to know what you are talking about. Just don't let what seems logical lead you down stray paths. Yes, on first glance the original problem appears to need a 80 lb strain but unfortunately it isn't true in real life. A simple test (or reference to any physics text) will show you in less than a minute. Harry K You didn't show how attaching the rope back to bucket is in anyway different than attaching to a separate anchor. You are still assuming a non-existant 40 lb load. It is the same load extended to the anchor or the bucket handle. The text book I did find did at least -mention- the force extending through the hook but did not specifically mention what the force was, i.e., was it 1/2 the load or the whole load. Harry, LOOK at the 1st diagram on this posting. The one that shows both ends of the rope attached to the 40lb load. You'll notice that both ends have 20lbs of tension. Two rope ends at 20lbs each is capable of supporting a 40lb load. Now LOOK at the 2nd diagram where one end of the rope is attached to the load and the other end is attached to an anchor. Now since there is only one end of the rope attached to the load, that end has to have 40 lbs of tension in order to support a 40 lb load. The other end of the rope also has to have 40 lbs of tension in order to keep it from running out of the pulley. Now LOOK at the 1st diagram again. Note that the rope is under 20 lbs of tension. Notice that the rope goes to and from the pulley for 2 force vectors from the pulley. Each vector has 20 lbs and 2 times 20 is 40. Once again LOOK at the 2nd diagram. Note that in this diagram the rope is under 40 lbs of tension. Once again, notice that the rope goes to and from the pulley for once again 2 force vectors. However, since the force vectors are now 40lbs instead of 20lbs, the force that the top pulley is having to support is now 40 times 2 for a total of 80 lbs. The tension in the rope doubles when going from both attachment points on the load to a single attachment point on the load and a single attachment point on an anchor. Personally, I enjoy teaching someone something and seeing the light bulb go off when the student realizes what is going on. But, I'll forgo that pleasure in your case since it seems that the bulb is burnt out. If you continue to ignore what everyone else in this newsgroup continues to say, then I can only come to one of three conclusions. 1. You're a idiot. 2. You're a liar. 3. You're a troll. I really don't care which of the above conclusions is the correct one since it's obvious that in all three cases the correct thing to do is to drop it and allow you to kill yourself off (hopefully before you reproduce) by killing yourself in the future by overloading a hoist due to your massive ignorance of physics. Later people. DON'T FEED THE TROLL Too bad. http://science.howstuffworks.com/pulley.htm Q: Where does this show the load on the support? A: It doesn't. Has a diagram with all force vectors clearly labeled, 2 100 down yeilding a 200 lb down force on the hook. Unfortunately there is also a 100 up vector that cancels one of the up for a remaining force of 100 lbs on the hook. Dolt. You can't even count. Look at the page, Harry. It shows *three* 100-lb vectors down and one up. Incidently I layed this same problem out for 6 different people ranging in eduction from a masters to HS. Every one got the right answer including a retired science teacher. IOW they all say you're full of beans? :-) Or is this another one of your lies, Harry? |
Figuring loads / block & tackle theory
In article , (Harry K) wrote:
(Doug Miller) wrote in message gy.com... In article , (Harry K) wrote: [snip] Test 2 - Rope over scale hook angle to anchor and tension eased several times before reading. Three tries. SCALE I O I \ I \ I \ I \ I \ I \ I Anchor 16 LB weight Readings: bucket scale 18 21 16 21 16 21 [snip] To all the naysayers out there. Do the damn test and be honest about your results. To you, Harry, I say: do the damn test and be honest about your results. Set it up like you show in that diagram above and report what the scale _at_the_top_ reads. Not the readings in the individual ropes. We're not talking about the loads in the individual ropes. That's completely irrelevant. The *only* point under discussion is the load _at_the_top. And see my reply to you above. That _is_ what was measured as is clear to anyone looking. OK, so assuming that you mean, by these two separate lists of weights, that when the bucket weighs 'x' the scale measures 'y' -- you're *still* left with the task of explaining how the scale could possibly measure anything higher than the weight of the bucket. -- Regards, Doug Miller (alphageek-at-milmac-dot-com) For a copy of my TrollFilter for NewsProxy/Nfilter, send email to autoresponder at filterinfo-at-milmac-dot-com |
Figuring loads / block & tackle theory
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Figuring loads / block & tackle theory
In article ,
Harry K wrote: SNIP... Too bad. http://science.howstuffworks.com/pulley.htm Has a diagram with all force vectors clearly labeled, 2 100 down yeilding a 200 lb down force on the hook. Unfortunately there is also a 100 up vector that cancels one of the up for a remaining force of 100 lbs on the hook. Incidently I layed this same problem out for 6 different people ranging in eduction from a masters to HS. Every one got the right answer including a retired science teacher. I can only hope you are not science instructor. If so, god help the education business. Harry K Once more into the fray. See http://www.drlaser.org/NEWRIG-sys.html and scroll down to figure 6. Read the text associated with that figure. Pay close attention to the forces upon the fixed pulleys. |
Figuring loads / block & tackle theory
"The Other Harry" wrote in message ... [On Wed, 17 Mar 2004 15:18:33 GMT, "Ray K." wrote:] Actually, you want the anchor as close as possible to the weight, not off at an angle. When it's some distance from the weight, depending on how the scale is attached to the ceiling (free to pivot or rigidly fixed), the scale will also measure some portion of the horizontal component of the rope's tension and increase its reading, something everyone has missed so far. (I know it won't make a 2:1 difference.) Interesting. This seems to contradict what Michael (who seems to know what he is talking about) said about the angle of the rope from the hook/pulley to the cleat. Unless I misunderstood, the more vertically down the rope goes once it leaves the hook, the greater the load on the hook. Alternatively, the more vertically up the rope goes, the less the load on the hook. Yes the angle of ther rope will make a differance, I guess I assumed no one was pulling at large angles from vertical. Greg |
Figuring loads / block & tackle theory
"Harry K" wrote in message om... " http://science.howstuffworks.com/pulley.htm Best I could find on the net. Do you see the force vector arrows in the diagram? They show 100 lbs down force on the right, 100 lbs up force on the right and another 100 lbs down force on the left. Notice the two 100 lbs down? Yep, that would mean 200 lbs on the hook. But wait a minute. There is one 100 lbs -up- force. That cancels one of the downs leaving I guess that rope is slack then, according to the drawings. Two 100 lbs forces, cancelling themselves out equal zero! You cite that web page time and time again, and it does not back up your arguement! It does not give a force at the pulley! Greg |
Figuring loads / block & tackle theory
Holy crap. There must be 100 posts sitting out here in this thread. Has -nobody- a clue for the solution?? There -must- be a conclusive Coyote/Roadrunner cartoon out there with the answer. Come on folks with the DVD's, help us out! -- TP / Network Man __________________________________ If u want the races for free, somebody has to pay for it. ($1 Earl) |
Figuring loads / block & tackle theory
While not directly applicable to the configuration discussed in this
thread, the following animated link is entertaining: http://www.walter-fendt.de/ph14e/pulleysystem.htm |
Figuring loads / block & tackle theory
"I-zheet M'drurz" wrote in message ... Holy crap. There must be 100 posts sitting out here in this thread. Has -nobody- a clue for the solution?? There -must- be a conclusive Coyote/Roadrunner cartoon out there with the answer. Come on folks with the DVD's, help us out! LOL!! The sad part is it has been answered, time and time again! Greg |
Figuring loads / block & tackle theory
"Doug Miller" wrote in message news:Q946c.35669 Read what I wrote, fool. I didn't say that anything on that site was wrong. I said it doesn't support your claims. And it doesn't. Yet you continue to falsely claim that it does. You're a liar, Harry. I find it interesting that there are at least six people in this thread that agree on the forces that occur in a pulley set up like we have been disscussing. At least two more posters have stated the Harry K is wrong, although not saying who is right. A couple of confused sorts have come through and not sided with anyone, just muttered thier confusion and left! At any rate that is a minimum of eight people that disagree with Harry K on this, with NO posters on his side of the arguement! Harry, I really think you should step back from this a re-think it all! If it makes you feel better, I looked through my engineering books tonight, I did find some information on pulleys and the loads created, but it is much to lengthy and in depth to reproduce here, and probably would just add to the confusion! But here are referance to the books. Engineering, An Introduction to a Creative Profession, Beakley and Leach, third edition, copyright 1977 Statics and Strenghts of Materials, Irving J. Levinson, copyright 1971 Pick them up Harry, read the relevent sections and get back with us! Greg |
Figuring loads / block & tackle theory
"Greg O" wrote in message ...
"Harry K" wrote in message om... " http://science.howstuffworks.com/pulley.htm Best I could find on the net. Do you see the force vector arrows in the diagram? They show 100 lbs down force on the right, 100 lbs up force on the right and another 100 lbs down force on the left. Notice the two 100 lbs down? Yep, that would mean 200 lbs on the hook. But wait a minute. There is one 100 lbs -up- force. That cancels one of the downs leaving I guess that rope is slack then, according to the drawings. Two 100 lbs forces, cancelling themselves out equal zero! You cite that web page time and time again, and it does not back up your arguement! It does not give a force at the pulley! Greg I cited once, it proves the poiint. Bye harry K |
Figuring loads / block & tackle theory
wrote in message .. .
Harry K wrote: snip Harry's trying to claim he isn't lying about his test Sorry for you. Here is the only one I found that comes close. It is some better than Tom's. Note that I have done the research, you haven't. http://science.howstuffworks.com/pulley.htm Best I could find on the net. Do you see the force vector arrows in the diagram? They show 100 lbs down force on the right, 100 lbs up force on the right and another 100 lbs down force on the left. Notice the two 100 lbs down? Yep, that would mean 200 lbs on the hook. But wait a minute. There is one 100 lbs -up- force. That cancels one of the downs leaving Count all the forces Harry. There's _three_ 100 lb down forces, and one 100 lb up force. That's two hundred pounds down, not that you care. You just proved you can't read a force diagram, there are 3 showing forces on the rope legs. The site proves my point. So bye. snip unread as you proved you don't understand the point Harry K John |
Figuring loads / block & tackle theory
(John Cochran) wrote in message ...
In article , Harry K wrote: SNIP... Too bad. http://science.howstuffworks.com/pulley.htm Has a diagram with all force vectors clearly labeled, 2 100 down yeilding a 200 lb down force on the hook. Unfortunately there is also a 100 up vector that cancels one of the up for a remaining force of 100 lbs on the hook. Incidently I layed this same problem out for 6 different people ranging in eduction from a masters to HS. Every one got the right answer including a retired science teacher. I can only hope you are not science instructor. If so, god help the education business. Harry K Once more into the fray. See http://www.drlaser.org/NEWRIG-sys.html and scroll down to figure 6. Read the text associated with that figure. Pay close attention to the forces upon the fixed pulleys. Go do the test. bye Harry K |
Figuring loads / block & tackle theory
(Doug Miller) wrote in message . com...
In article , (Harry K) wrote: (Doug Miller) wrote in message gy.com... In article , (Harry K) wrote: Douglas and Rosemarie Miller wrote in message gy.com... In article , says... [big snip] Someone way up thread posted at link to a site giving the good explanation. Once again, Harry, you're caught in a lie. The site posted does *not* support your position here, despite your false claim that it does. Here's the relevant part of the post you refer to: http://www.howstuffworks.com/pulley.htm This web page speaks to the issue of how much pull is needed on the rope to make the weight go up. But it does not adress the felt weight on the pulley hook. Note that last sentence, Harry: "does not adress [sic] the weight on the hook". And just where did I say that it did? I said that someone had posted a link, you found it. I didn't read it. You apparently haven't read very much of anything -- including what you yourself have written. You said that the link was to "a site giving the good explanation." In fact, that site doesn't explain *anything* that is relevant to this discussion. One citation, Harry, just *one*, of a published source that supports your claims. Just one. We're waiting. See below. I gave a cite and jsut as I predicted you said it was wrong. Harry, when are you going to stop lying? I did _not_ say the site was wrong. I said it does not support your claims. And it doesn't. But you continue to falsely claim that it does, even though it never mentions the one point that we're arguing about. You're a liar, Harry. Again, I predicted you would say it doesn't you did, you didn't prove it (you can't). so Bye Harry K |
Figuring loads / block & tackle theory
"Ray K." wrote in message t...
Doug Miller wrote: Big snip Then I suggest you do the test: arrange the weight, scale, and anchor as shown in your diagram above and reproduced he SCALE I O I \ I \ I \ I \ I \ I \ I Anchor 16 LB weight and report what the scale at the top reads. Actually, you want the anchor as close as possible to the weight, not off at an angle. When it's some distance from the weight, depending on how the scale is attached to the ceiling (free to pivot or rigidly fixed), the scale will also measure some portion of the horizontal component of the rope's tension and increase its reading, something everyone has missed so far. (I know it won't make a 2:1 difference.) BTW, some of you referred to the How Stuff Works link, http://www.howstuffworks.com/pulley.htm, for supposedly an authorative explanation of pulleys (even though it doesn't address the issue here). I see their third figure, the one with one pulley at the weight and the other at the ceiling, as wrong. At the weight, the rope changes angle about 60 degrees; that is, each is about 30 degrees from the vertical. The vertical component of "each" rope's tension must be 50 pounds. Therefore, the tension in the rope must be 50/cosine 30 = 50/.866 = 57.5 pounds. Lesson: Don't trust even fancy websites to get simple basics right. Yes you are correct. I didn't want to get into the angle question. I thought about it a couple of times but just figured it would complicate things. If you are on the 1x side of things, don't bother talking to them. They will not believe anything that goes against their firm beliefs. Harry K |
Figuring loads / block & tackle theory
"Ray K." wrote in message t...
Doug Miller wrote: Big snip Then I suggest you do the test: arrange the weight, scale, and anchor as shown in your diagram above and reproduced he SCALE I O I \ I \ I \ I \ I \ I \ I Anchor 16 LB weight and report what the scale at the top reads. Actually, you want the anchor as close as possible to the weight, not off at an angle. When it's some distance from the weight, depending on how the scale is attached to the ceiling (free to pivot or rigidly fixed), the scale will also measure some portion of the horizontal component of the rope's tension and increase its reading, something everyone has missed so far. (I know it won't make a 2:1 difference.) BTW, some of you referred to the How Stuff Works link, http://www.howstuffworks.com/pulley.htm, for supposedly an authorative explanation of pulleys (even though it doesn't address the issue here). I see their third figure, the one with one pulley at the weight and the other at the ceiling, as wrong. At the weight, the rope changes angle about 60 degrees; that is, each is about 30 degrees from the vertical. The vertical component of "each" rope's tension must be 50 pounds. Therefore, the tension in the rope must be 50/cosine 30 = 50/.866 = 57.5 pounds. Lesson: Don't trust even fancy websites to get simple basics right. Yes you are correct. I didn't want to get into the angle question. I thought about it a couple of times but just figured it would complicate things. If you are on the 1x side of things, don't bother talking to them. They will not believe anything that goes against their firm beliefs. Harry K |
Figuring loads / block & tackle theory
(Doug Miller) wrote in message om...
In article , (Harry K) wrote: (Doug Miller) wrote in message Test 2 - Rope over scale hook angle to anchor and tension eased several times before reading. Three tries. SCALE I O I \ I \ I \ I \ I \ I \ I Anchor 16 LB weight Readings: bucket scale 18 21 16 21 16 21 The readings you report are not consistent with your diagram, which shows only one scale at the top. You purport to have made two force measurements with only one scale. Nice trick. WTF?? what two force measurements are you talking about now? "Bucket" and "scale". Just like you posted. What are those? snip the usual denial bs Of course I listed bucket and scale. It is two separate measurements. Bucket alone, then the rig. Can't you read or understand plain english and clear (very) diagrams? Don't both answering this as I won't bother to read it. I am signing off to all the correspondents as you have all proved you will not accept anything, not even valid citations that go against your beliefs. Harry K |
Figuring loads / block & tackle theory
In article , (Harry K) wrote:
"Greg O" wrote in message ... "Harry K" wrote in message om... " http://science.howstuffworks.com/pulley.htm Best I could find on the net. Do you see the force vector arrows in the diagram? They show 100 lbs down force on the right, 100 lbs up force on the right and another 100 lbs down force on the left. Notice the two 100 lbs down? Yep, that would mean 200 lbs on the hook. But wait a minute. There is one 100 lbs -up- force. That cancels one of the downs leaving I guess that rope is slack then, according to the drawings. Two 100 lbs forces, cancelling themselves out equal zero! You cite that web page time and time again, and it does not back up your arguement! It does not give a force at the pulley! Greg I cited once, it proves the poiint. Give it up, Harry. It does *not* prove your point: it _never_mentions_ the load at the top anchor. Anyone can look at the page and see that. |
Figuring loads / block & tackle theory
In article , (Harry K) wrote:
(John Cochran) wrote in message ... In article , Harry K wrote: SNIP... Too bad. http://science.howstuffworks.com/pulley.htm Has a diagram with all force vectors clearly labeled, 2 100 down yeilding a 200 lb down force on the hook. Unfortunately there is also a 100 up vector that cancels one of the up for a remaining force of 100 lbs on the hook. Incidently I layed this same problem out for 6 different people ranging in eduction from a masters to HS. Every one got the right answer including a retired science teacher. I can only hope you are not science instructor. If so, god help the education business. Harry K Once more into the fray. See http://www.drlaser.org/NEWRIG-sys.html and scroll down to figure 6. Read the text associated with that figure. Pay close attention to the forces upon the fixed pulleys. Go do the test. Harry, the test has been done. And the test proves you wrong. And don't tell us that you've done the test, and it proved you right. Your posts are archived in Google, and they show that you simply didn't tell the truth. Example: http://www.google. com/groups?q=g: thl890848697d&dq=&hl=en&lr=lang_en&ie=UTF-8&oe=UTF-8&selm=751f8d35.0403150836. 68215d5e%40posting.google.com&rnum=117 reproduced in part he [begin quote] Don't bother, he won't believe you but just to prove it -again- I just re-ran the experiment. Bucket weighed 26 lbs this time scale reads 26 (taa daa!) I\ I \ I \ I \ I \ I \ I \ bucket anchor 26 lb [end quote] This is just plain false, Harry. Anybody can repeat this test, and see for himself that when configured the way you show it, the reading is quite far from what you claim it to be. Either your diagram is false, or your numbers are false, or you never did the test. |
Figuring loads / block & tackle theory
In article , (Harry K) wrote:
(Doug Miller) wrote in message . com... In article , (Harry K) wrote: (Doug Miller) wrote in message gy.com... In article , (Harry K) wrote: Douglas and Rosemarie Miller wrote in message gy.com... In article , says... [big snip] Someone way up thread posted at link to a site giving the good explanation. Once again, Harry, you're caught in a lie. The site posted does *not* support your position here, despite your false claim that it does. Here's the relevant part of the post you refer to: http://www.howstuffworks.com/pulley.htm This web page speaks to the issue of how much pull is needed on the rope to make the weight go up. But it does not adress the felt weight on the pulley hook. Note that last sentence, Harry: "does not adress [sic] the weight on the hook". And just where did I say that it did? I said that someone had posted a link, you found it. I didn't read it. You apparently haven't read very much of anything -- including what you yourself have written. You said that the link was to "a site giving the good explanation." In fact, that site doesn't explain *anything* that is relevant to this discussion. One citation, Harry, just *one*, of a published source that supports your claims. Just one. We're waiting. See below. I gave a cite and jsut as I predicted you said it was wrong. Harry, when are you going to stop lying? I did _not_ say the site was wrong. I said it does not support your claims. And it doesn't. But you continue to falsely claim that it does, even though it never mentions the one point that we're arguing about. You're a liar, Harry. Again, I predicted you would say it doesn't you did, you didn't prove it (you can't). so Bye Harry, it's time to seek professional help. |
Figuring loads / block & tackle theory
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Figuring loads / block & tackle theory
I am a heating and AC guy. I installed furnaces for about three years.
And I wish you would leave enough of the original question so that we would know WHAT is wrong. Harrry K has written at least four or five posts under this header. We have simply no way to know which of his four or five posts are being contradicted, here. -- Christopher A. Young Learn more about Jesus www.lds.org www.mormons.com "Michael Daly" wrote in message ... On 14-Mar-2004, (Harry K) wrote: ask a physics teacher I'm an engineer, I was a physics teacher in grad school and you are wrong. Mike |
Figuring loads / block & tackle theory
I may someday find a spring scale and try this out. Curiosity is getting to
me. -- Christopher A. Young Learn more about Jesus www.lds.org www.mormons.com "Harry K" wrote in message m... "Greg O" wrote in message ... Stormy, you have proven again, without a doubt that you do not know what you are talking about! Well stormin, don't bother to try it as Greg won't believe the readings anyhow. And take note that Greg refuses to do the experiment. Teh best you can hope for is an F Harry K A sig I saw somewhe Two bad stupidity isn't painful. At least ignorance can be cured if one wants to learn. Harry K |
Figuring loads / block & tackle theory
Harry K wrote:
wrote in message .. . Harry K wrote: snip Harry's trying to claim he isn't lying about his test Sorry for you. Here is the only one I found that comes close. It is some better than Tom's. Note that I have done the research, you haven't. http://science.howstuffworks.com/pulley.htm Best I could find on the net. Do you see the force vector arrows in the diagram? They show 100 lbs down force on the right, 100 lbs up force on the right and another 100 lbs down force on the left. Notice the two 100 lbs down? Yep, that would mean 200 lbs on the hook. But wait a minute. There is one 100 lbs -up- force. That cancels one of the downs leaving Count all the forces Harry. There's _three_ 100 lb down forces, and one 100 lb up force. That's two hundred pounds down, not that you care. You just proved you can't read a force diagram, there are 3 showing forces on the rope legs. The site proves my point. So bye. snip unread as you proved you don't understand the point Aha, so you read it and found that it refuted your position so clearly that you couldn't keep on with your nonsense, huh? That's good, I was hoping that someone could finally get through to you and I'm glad it was me. Carry on with your pointless denials to try and save face. My job here is done. John -- Remove the dead poet to e-mail, tho CC'd posts are unwelcome. Ask me about joining the NRA. |
Figuring loads / block & tackle theory
In article , "Stormin Mormon" wrote:
I may someday find a spring scale and try this out. Curiosity is getting to me. Actually, Stormy, you don't even need a spring scale. All you need is something heavy (a loaded toolbox works quite well), a pulley, and some rope. First pick up the toolbox and set it down again so you get a feel for how heavy it is. Next, cut off a little of the rope to make a handle for the pulley. Tie one end of the rest of the rope to the toolbox handle, pass the rope through the pulley, then stand on the other end of the rope. Now pick up the toolbox by lifting the pulley. You'll feel the difference, believe me. It's not very scientific, I know, but you will be convinced. |
Figuring loads / block & tackle theory
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Figuring loads / block & tackle theory
Harry: While you're at the apologizing, look up "abject" in your dictionary
and see if you don't want to rephrase your apology! LOL!! Dave "Harry K" wrote in message om... (Doug Miller) wrote in message om... In article , "Stormin Mormon" wrote: I may someday find a spring scale and try this out. Curiosity is getting to me. Actually, Stormy, you don't even need a spring scale. All you need is something heavy (a loaded toolbox works quite well), a pulley, and some rope. First pick up the toolbox and set it down again so you get a feel for how heavy it is. Next, cut off a little of the rope to make a handle for the pulley. Tie one end of the rest of the rope to the toolbox handle, pass the rope through the pulley, then stand on the other end of the rope. Now pick up the toolbox by lifting the pulley. You'll feel the difference, believe me. It's not very scientific, I know, but you will be convinced. My abject apologies to everyone involved in this fiasco. Most especially I apologize to Doug, he had it nailed all the way. What brings me to this? I had to rig an exercise machine for my leg - cable thru pulleys to a weight. After finishing, I decided to use it as one final test. This is the only bright thing I did in the entire thing. It showed clearly that you all were right. Now just how could I have been doing tests and getting the reading I was that showed I was right. As Doug said, operator error. But that wasn't enough for me. When I set out to be stupid, just one isn't enough, I had to pile stupidity on stupidity. 1. Being absolutely certain I was right, thus believed my test results. 2. Poor choice of tools. They were perfectly adequate but a better scale would have showed the error. 3. Error in setting up the test. 4. Not recognizing (or even thinking) about the error even after *I* posted it in plain English. As stated I ran one test on a good set-up. It showed that indeed the hook stress is 2x the weight. Returned to my orginal set-up (crude) and stared at it, still didn't see it. Went shopping (50 mile drive) thinking about it before it dawned. The set-up/tool error came down to the scale. It only read to 25 lbs. If you recall my test results, my weight was (I think) 22 lbs. I kept lowing it in two or 3 steps down to 16 lbs. At 16 lbs I posted that the errors I was seeing (only slight variations from what I expected to see) "could have been that I was measuring at the top of the scale" and also mentioned that the scale was only 25 lb. This should have tipped me. I am rather surprised in retrospect that none of you called me on it as you are one bright bunch. Of course I was getting the results I expected. The scale/weight I was using would not allow any other result. 22 lbs is almost top scale thus couldn't possibly show a reading over 1x much less 2x. 16 lbs was still way to much but did allow enough to give a clue. I didn't spot it. I wonder if I would have seen it if I had dropped the weight to 12 lbs. Somehow on my crude set-up I suspect I would have found a way to rationalize it. Again, my abject apologies to all but especially to Doug. Harry K |
Figuring loads / block & tackle theory
In article , "Dave" wrote:
Harry: While you're at the apologizing, look up "abject" in your dictionary and see if you don't want to rephrase your apology! LOL!! Dave Oh, I dunno. My dictionary gives sense (3) as "shamelessly servile". Overstates the case, perhaps, but fits. :-) "Harry K" wrote in message . com... (Doug Miller) wrote in message . com... In article , "Stormin Mormon" wrote: I may someday find a spring scale and try this out. Curiosity is getting to me. Actually, Stormy, you don't even need a spring scale. All you need is something heavy (a loaded toolbox works quite well), a pulley, and some rope. First pick up the toolbox and set it down again so you get a feel for how heavy it is. Next, cut off a little of the rope to make a handle for the pulley. Tie one end of the rest of the rope to the toolbox handle, pass the rope through the pulley, then stand on the other end of the rope. Now pick up the toolbox by lifting the pulley. You'll feel the difference, believe me. It's not very scientific, I know, but you will be convinced. My abject apologies to everyone involved in this fiasco. Most especially I apologize to Doug, he had it nailed all the way. What brings me to this? I had to rig an exercise machine for my leg - cable thru pulleys to a weight. After finishing, I decided to use it as one final test. This is the only bright thing I did in the entire thing. It showed clearly that you all were right. Now just how could I have been doing tests and getting the reading I was that showed I was right. As Doug said, operator error. But that wasn't enough for me. When I set out to be stupid, just one isn't enough, I had to pile stupidity on stupidity. 1. Being absolutely certain I was right, thus believed my test results. 2. Poor choice of tools. They were perfectly adequate but a better scale would have showed the error. 3. Error in setting up the test. 4. Not recognizing (or even thinking) about the error even after *I* posted it in plain English. As stated I ran one test on a good set-up. It showed that indeed the hook stress is 2x the weight. Returned to my orginal set-up (crude) and stared at it, still didn't see it. Went shopping (50 mile drive) thinking about it before it dawned. The set-up/tool error came down to the scale. It only read to 25 lbs. If you recall my test results, my weight was (I think) 22 lbs. I kept lowing it in two or 3 steps down to 16 lbs. At 16 lbs I posted that the errors I was seeing (only slight variations from what I expected to see) "could have been that I was measuring at the top of the scale" and also mentioned that the scale was only 25 lb. This should have tipped me. I am rather surprised in retrospect that none of you called me on it as you are one bright bunch. Of course I was getting the results I expected. The scale/weight I was using would not allow any other result. 22 lbs is almost top scale thus couldn't possibly show a reading over 1x much less 2x. 16 lbs was still way to much but did allow enough to give a clue. I didn't spot it. I wonder if I would have seen it if I had dropped the weight to 12 lbs. Somehow on my crude set-up I suspect I would have found a way to rationalize it. Again, my abject apologies to all but especially to Doug. Harry K |
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