Help identifying components
Does the fact that both show ~ 0.6 v-drop rule out zeners?
Thanks. |
Help identifying components
"DaveC" wrote in message ... Does the fact that both show ~ 0.6 v-drop rule out zeners? Thanks. No, only that they are most likely silicon. The zener effect is the reverse breakdown voltage. You need to dope out the circuit more to see if it could be a zener. |
Help identifying components
DaveC wrote in
: Does the fact that both show ~ 0.6 v-drop rule out zeners? Thanks. You sound like a man who imagines that by scrunchign his shoulders, no-one will mind when he passes annopyingly several times through the same doorway. :) And no. To test a zener you need to try a reverse voltage. Try a variable voltage through a 10K resistor. A sine wave off a 30V transformer will do, just look for the clipping voltages on a scope (or DC voltmeter if you add a capacitor in parallel with the diode). Vz equals peak-peak voltage minus about 0.58V. You may also have to remove one end of it from the circuit to be certain. |
Help identifying components
Lostgallifreyan wrote in
: Vz equals peak-peak voltage minus about 0.58V. Evidently my turn to pass annoying through the same doorway... Scratch that, the rest stands though, you just have to do the test once for each polarity of that diode. (You'll only see both peaks at once if you have a zero-referenced AC voltage, and even then that capacitor idea wouldn't apply, and I made it more complex than it needs to be, you only need to see the zener peak to know...). |
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