Two Cap Puzzle
On Thu, 15 Jul 2010 23:37:35 -0500, flipper wrote:
On Thu, 15 Jul 2010 17:59:57 -0700, Jim Thompson wrote: On Thu, 15 Jul 2010 18:45:33 -0500, flipper wrote: On Thu, 15 Jul 2010 13:35:09 -0700, "Paul Hovnanian P.E." wrote: My solution for the missing energy. I'm not sure what inspired the analysis but you don't need two capacitors to express the 'conundrum' as you've got it in the very first term for E in a charged capacitor. From the definition of C, q, V, and E one might expect E, in an 'ideal' capacitor, to be qV or, by substitution, C*V^2 but, as you point out, it's commonly known to be .5*C*V^2. Where did the missing energy go? The answer is the same, dissipated in the R 0, and is inherent to the charging of a capacitor whether it is from a battery or, in your case, another capacitor. Trying to postulate an 'ideal' circuit with R=0 leads to the impossibility of an instantaneous charge of infinite current and with electron mobility limited by the speed of light the universe, as we understand things, simply can't do it. Flipper, _In_the_limit_ as R-0 the exact same amount of energy is lost as with a finite R. Try it, you'll like it :-) I understand your point and one of the endearing things about math is you can calculate the impossible but in this case I think it is more confounding than illuminating as most people will likely have difficulty estimating the dissipation of infinite current through 0 ohms. So why bother confounding the matter with a singularity that cannot exist? ...Jim Thompson What singularity? No singularity needed. Thimk. |
Two Cap Puzzle
On Wed, 21 Jul 2010 02:32:51 -0500, flipper wrote:
On Tue, 20 Jul 2010 21:45:23 -0700, wrote: On Thu, 15 Jul 2010 23:37:35 -0500, flipper wrote: On Thu, 15 Jul 2010 17:59:57 -0700, Jim Thompson wrote: On Thu, 15 Jul 2010 18:45:33 -0500, flipper wrote: On Thu, 15 Jul 2010 13:35:09 -0700, "Paul Hovnanian P.E." wrote: My solution for the missing energy. I'm not sure what inspired the analysis but you don't need two capacitors to express the 'conundrum' as you've got it in the very first term for E in a charged capacitor. From the definition of C, q, V, and E one might expect E, in an 'ideal' capacitor, to be qV or, by substitution, C*V^2 but, as you point out, it's commonly known to be .5*C*V^2. Where did the missing energy go? The answer is the same, dissipated in the R 0, and is inherent to the charging of a capacitor whether it is from a battery or, in your case, another capacitor. Trying to postulate an 'ideal' circuit with R=0 leads to the impossibility of an instantaneous charge of infinite current and with electron mobility limited by the speed of light the universe, as we understand things, simply can't do it. Flipper, _In_the_limit_ as R-0 the exact same amount of energy is lost as with a finite R. Try it, you'll like it :-) I understand your point and one of the endearing things about math is you can calculate the impossible but in this case I think it is more confounding than illuminating as most people will likely have difficulty estimating the dissipation of infinite current through 0 ohms. So why bother confounding the matter with a singularity that cannot exist? ...Jim Thompson What singularity? The one he proposed. Which one, that who proposed, in which post? No singularity needed. And a good thing too since it's impossible. Thimk. Try it some time. |
Two Cap Puzzle
On Fri, 23 Jul 2010 21:43:42 -0500, flipper wrote:
On Fri, 23 Jul 2010 19:35:03 -0700, wrote: On Wed, 21 Jul 2010 02:32:51 -0500, flipper wrote: On Tue, 20 Jul 2010 21:45:23 -0700, wrote: On Thu, 15 Jul 2010 23:37:35 -0500, flipper wrote: On Thu, 15 Jul 2010 17:59:57 -0700, Jim Thompson wrote: On Thu, 15 Jul 2010 18:45:33 -0500, flipper wrote: On Thu, 15 Jul 2010 13:35:09 -0700, "Paul Hovnanian P.E." wrote: My solution for the missing energy. I'm not sure what inspired the analysis but you don't need two capacitors to express the 'conundrum' as you've got it in the very first term for E in a charged capacitor. From the definition of C, q, V, and E one might expect E, in an 'ideal' capacitor, to be qV or, by substitution, C*V^2 but, as you point out, it's commonly known to be .5*C*V^2. Where did the missing energy go? The answer is the same, dissipated in the R 0, and is inherent to the charging of a capacitor whether it is from a battery or, in your case, another capacitor. Trying to postulate an 'ideal' circuit with R=0 leads to the impossibility of an instantaneous charge of infinite current and with electron mobility limited by the speed of light the universe, as we understand things, simply can't do it. Flipper, _In_the_limit_ as R-0 the exact same amount of energy is lost as with a finite R. Try it, you'll like it :-) I understand your point and one of the endearing things about math is you can calculate the impossible but in this case I think it is more confounding than illuminating as most people will likely have difficulty estimating the dissipation of infinite current through 0 ohms. So why bother confounding the matter with a singularity that cannot exist? ...Jim Thompson What singularity? The one he proposed. Which one, that who proposed, in which post? Not going to get very far till you learn how to read. No singularity needed. And a good thing too since it's impossible. Thimk. Try it some time. And properly "layer quote" ...Jim Thompson -- | James E.Thompson, CTO | mens | | Analog Innovations, Inc. | et | | Analog/Mixed-Signal ASIC's and Discrete Systems | manus | | Phoenix, Arizona 85048 Skype: Contacts Only | | | Voice:(480)460-2350 Fax: Available upon request | Brass Rat | | E-mail Icon at http://www.analog-innovations.com | 1962 | Spice is like a sports car... Only as good as the person behind the wheel. |
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