Engine run time to keep battery charged
On Tue, 5 Feb 2019 01:30:54 -0000 (UTC), arlen holder wrote:
Let's assume it takes five to ten seconds to start it, at 500 amps, where
the maximum _power _would be 10 seconds times 500 amps, which means you
sucked out 5,000 Coulombs (i.e., 5000 amp seconds) if the math is right.
Ooops... Coulombs ... not power... (power would be via P=IV or I^2R but
not amp seconds)...
(I hacked that out in a minute on the run, so, please correct where I err.)